4^1/3=(x-5)^2/3

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Solution for 4^1/3=(x-5)^2/3 equation: 


x in (-oo:+oo)

(4^1)/3 = ((x-5)^2)/3 // - ((x-5)^2)/3

(4^1)/3-(((x-5)^2)/3) = 0

4/3-(((x-5)^2)/3) = 0

(-1*(x-5)^2)/3+4/3 = 0

4-1*(x-5)^2 = 0

10*x-x^2-21 = 0

10*x-x^2-21 = 0

10*x-x^2-21 = 0

DELTA = 10^2-(-21*(-1)*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)-10)/(-1*2) or x = (-16^(1/2)-10)/(-1*2)

x = 3 or x = 7

(x-3)*(x-7) = 0

((x-3)*(x-7))/3 = 0

((x-3)*(x-7))/3 = 0 // * 3

(x-3)*(x-7) = 0

( x-3 )

x-3 = 0 // + 3

x = 3

( x-7 )

x-7 = 0 // + 7

x = 7

x in { 3, 7 }

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